Re: [xsl] Getting the root namespace from the input document

["Andrew Welch" <andrew.j.welch@xxxxxxxxx>]

On 2/5/07, Mukul Gandhi <gandhi.mukul@xxxxxxxxx> wrote:
> On 2/5/07, Andrew Welch <andrew.j.welch@xxxxxxxxx> wrote:
> > <xsl:template match="/">
> >        <Metadata>
> >                <xsl:copy-of select="namespace::node()"/>
> >        </Metadata>
> > </xsl:template>
>
> I think Andrew means:
>
> <xsl:template match="/manifest">
>    <Metadata>
>       <xsl:copy-of select="namespace::*"/>
>    </Metadata>
> </xsl:template>

I did, well spotted!

> But namespace:: axis is deprecated in XSLT 2.0 (though, Saxon supports it)

That's interesting... wasn't aware of that.

> If you are using XSLT 2.0, the following is perhaps a portable way:
>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="2.0">
>
> <xsl:output method="xml" indent="yes" />
>
> <xsl:template match="manifest">
>   <xsl:variable name="x" select="." />
>   <Metadata>
>     <!-- create namespace declarations -->
>     <xsl:for-each select="in-scope-prefixes($x)">
>       <xsl:namespace name="{.}"><xsl:value-of
> select="namespace-uri-for-prefix(., $x)" /></xsl:namespace>
>     </xsl:for-each>
>
>     <!-- do rest of things -->
>   </Metadata>
> </xsl:template>
>
> </xsl:stylesheet>

That's really cool too.  This is all news to me - I didn't think the
prefixes were available to the XSLT processor...?