Re: [xsl] for-each select="position()"

[Abel Braaksma <abel.online@xxxxxxxxx>]

John Cavalieri wrote:
> The following appears to work with the latest Saxon in an XSLT v2 
> style sheet.
>    <xsl:for-each select="position()">
>
> My take on this is that position() returns a number and that number is
> then used in a sequence of one.  Am I understanding this correctly and
> should this be how all XSLT v2 processors behave?

I am not 100%, but I think that position() returns a sequence of (1 or 
more) integers indicating the position of the element. For instance:

<xsl:for-each select="//position()">
  number: <xsl:value-of select="." />
</xsl:for-each>

will output all descendent-or-self element positions. And this:

<xsl:for-each select="position()">

will return the sequence of positions of the context node, always 
consisting of one item of xs:integer. Note, however, that it resembles, 
but is not the same, as:

<xsl:for-each select="self::node()/position()">
or
<xsl:for-each select="current()/position()">

which will both return 1, always.

-- Abel