Re: [xsl] XPath selecting chain of following siblings of the same name

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2007-03-10 17:13 +0530, Mukul Gandhi wrote:
> I wonder, why this XSLT 1.0 solution doesn't work:

From what I can tell it is because you only look at the "next" a and 
not all contiguous a elements that follow:

>     <xsl:apply-templates select="following-sibling::*[1][self::a]" />

Did you mean to do what is in the code below?  This appears to work just fine.

I hope this helps.

. . . . . . . . . Ken

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">

<xsl:output method="xml" indent="yes"/>

<!--identity transform for all nodes other than 'a'-->
<xsl:template match="node() | @*">
  <xsl:copy>
    <xsl:apply-templates select="node() | @*" />
  </xsl:copy>
</xsl:template>

<!--the first a-->
<xsl:template match="a[not(preceding-sibling::*[1][self::a])]">
  <a-block>
    <xsl:apply-templates select="." mode="nested"/>
  </a-block>
</xsl:template>

<!--other a's when nested-->
<xsl:template match="a" mode="nested">
  <xsl:copy-of select="."/>
  <xsl:apply-templates select="following-sibling::*[1][self::a]"
                       mode="nested"/>
</xsl:template>

<!--other a's when not nested can be ignored-->
<xsl:template match="a"/>

</xsl:stylesheet>


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