Subject: Re: [xsl] Finding distinct nodes using a function in XSLT 2.0 From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Tue, 17 Apr 2007 13:50:49 -0700 |
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
<xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:variable name="vDoc1" as="document-node()" select="document('file:///C:/XSLT/Tests/docFoo1.xml')"/>
<xsl:variable name="vDoc2" as="document-node()" select="document('file:///C:/XSLT/Tests/docFoo2.xml')"/>
<xsl:template match="/"> <foo> <xsl:for-each-group select="($vDoc1 | $vDoc2)/*/bar" group-by="@id"> <xsl:sort select="current-grouping-key()"/> <xsl:sequence select="."/> </xsl:for-each-group> </foo> </xsl:template> </xsl:stylesheet>
-- Cheers, Dimitre Novatchev --------------------------------------- Truly great madness cannot be achieved without significant intelligence. --------------------------------------- To invent, you need a good imagination and a pile of junk ------------------------------------- You've achieved success in your field when you don't know whether what you're doing is work or play
This probably isn't the easiest way to this (suggestions welcome), but I'm collecting data from two similarly structured source documents and wanting to build a set of distinct nodes based on a certain attribute value. Example XML:
doc1.xml <foo> <bar id="a" /> <bar id="b" /> <bar id="c" /> <bar id="d" /> <bar id="g" /> </foo>
doc2.xml <foo> <bar id="a" /> <bar id="b" /> <bar id="c" /> <bar id="d" /> <bar id="e" /> <bar id="f" /> </foo>
Desired resulting node set:
<foo> <bar id="a" /> <bar id="b" /> <bar id="c" /> <bar id="d" /> <bar id="e" /> <bar id="f" /> <bar id="g" /> </foo>
I'm required to provide a template function (or equivalent set of templates which returns a node set for use by various for-each constructs in other processors) which accepts the xpath (e.g. /foo/bar) and an index attribute (e.g. "id") as parameters and returns a node set as seen above.
I've managed to write a function which generates a sorted union (I think I need them sorted to find the distinct values, correct? sorry, newbie here..), but have yet to find a way to trim the results set so that it contains only distinct members. Here's what I have so far:
<xsl:variable name="compare_file" select="document('doc2.xml')"/> <xsl:variable name="current_file" select="document('doc1.xml')"/>
<xsl:function name="con:distinct_rows"> <!-- Selects the distinct rows from the source docs and --> <!-- comparison doc --> <xsl:param name="path"/> <xsl:param name="key"/> <xsl:variable name="source_rows" select="$current_file/saxon:evaluate($path)"/> <xsl:variable name="compare_rows" select="$compare_file/saxon:evaluate($path)"/> <xsl:variable name="sorted_union_rows"> <xsl:for-each select="$source_rows | $compare_rows"> <xsl:sort data-type="text" select="./saxon:evaluate($key)"/> <xsl:sequence select="."/> </xsl:for-each> </xsl:variable> <xsl:sequence select="$sorted_union_rows"/> <!-- ??? distinct node selector instead ??? --> </xsl:function>
Once I have the sorted union, I've tried various following/previous sibling selectors but have yet to find a command which generates the distinct node set (I can find the unique nodes based on the "id" but that's not really helping me).
Any suggestions?
thanks a lot! Scott Lynch
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