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Re: [xsl] Output fixed length records using mod operators to group results

Subject: Re: [xsl] Output fixed length records using mod operators to group results
From: Chris <ryder.roundabout@xxxxxxxxx>
Date: Thu, 10 May 2007 23:11:13 -0400
Wow!

Thanks (again!) David.

I was able to understand why everything works the way it works except
the for-each within the last container condition. Can you elaborate on
that?  It does exactly what I need it to do, but I'd sure like to know
why!

The section I'm referring to is:
    <xsl:if test="position()=last()">
      <xsl:for-each select="(//*)[position()&lt;= ((4000 -last() )mod 4)]">
        <xsl:value-of select="$field"/>
      </xsl:for-each>
    </xsl:if>

I'm not familiar with the (//*) expression, nor can I grasp the math
behind the predicate in that xpath (literature major as an undergrad).

Thanks,
Chris

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