Re: [xsl] complicated sort problem

[Vaduvoiu Tiberiu <vaduvoiutibi@xxxxxxxxx>]

fileX.xml:

<document>
    <date>20071805101800</date>(yyyymmddhhmmss)
   <url>folderX/foldery/</url>
    <other tags that aren't to interest>
</document>

I know the shorter solution would be to have a date attribute to the <list> xml file like <file date="2007...">file1.xml</file> 

But it's a little more complicated than that, I can't really put the data as an attribute so I need to do it with the xml-s structured like that.
10x. Cheers


----- Original Message ----
From: Dimitre Novatchev <dnovatchev@xxxxxxxxx>
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Sent: Wednesday, May 16, 2007 2:42:58 PM
Subject: Re: [xsl] complicated sort problem


On 5/16/07, Vaduvoiu Tiberiu <vaduvoiutibi@xxxxxxxxx> wrote:
> Similar problem with the one I had yesterday:
> I need to sort the following xml:
>
> <list>
>    <file>file1.xml</file>
>    <file>file2.xml</file>
> ......
>    <file>file100.xml</file>
> </list>
>
> each of these files have some tags (2 of which are:)
>    <date>20071805101800</date>(yyyymmddhhmmss)
>    <url>folderX/foldery/</url>
>
> So I need to sort the first xml by the date (which is in each fileX.xml). Is that possible? .


The short answer is: Yes.

A more specific solution with code could be produced, once the structure of the

       file<N>.xml

files is known.

-- 
Cheers,
Dimitre Novatchev
---------------------------------------
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