[xsl] xslt sort remove duplicates

[Vaduvoiu Tiberiu <vaduvoiutibi@xxxxxxxxx>]

I have an xml file that has a lot of entries which have a name, category and date. I need to display the most recent name of each categoryI To be more precise:..

I did this so far:

    <xsl:for-each select="exsl:node-set($mobile)/rootb/level1"> 
       <xsl:sort order="descending" select="categ"/>
        <xsl:sort order="descending" select="date"/>

<xsl:value-of select="titlu"/> -<xsl:value-of select="categ"/> - <xsl:value-of select="date"/>

</xsl:for-each>

right now my list looks like this: it's sorted after categoory, then it's sorted after date.

name1- category1 - most recent date *
name2 - category1 - date
name3 - category1 - date
name4 - category1 - date
name5 - category1 - date

name6 - category2 -  most recent date *
name7 - category2 - date
name8 - category2 - date
name9 - category2 - date
nameX - category2 - date

name6 - category3 -  most recent date *
name7 - category3 - date
name8 - category3 - date
name9 - category3 - date
nameX - category3 - date
........

I need to dsiplay only the one with the star. So I should only display:

name1- category1 - most recent date *

name6 - category2 -  most recent date *

I tried using an if not ((preceding:...but it doesn't work. I think I'm not writing the sintax correctly. Can anyone give some pointers ? 10x

name6 - category3 -  most recent date *


       
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