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Subject: [xsl] order as defined in the sequence From: Merico Raffaele <raffaele.merico@xxxxxxx> Date: Wed, 23 May 2007 14:48:40 +0200 |
Dear Community
Is there any possibility to set the order of the selected nodes as defined
in the sequence. I.E.
<xsl:for-each select="/node[@class = ('z', 'a', 'b')]">
I would like to process the nodes exactly as defined in the sequence z-a-b,
that means:
1) node[@class eq 'z']
2) node[@class eq 'a']
3) node[@class eq 'b']
Or do I have to use 3 <xsl:apply-templates/>.
For your support many thanks in advance ... Raffaele
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