Re: [xsl] How to get element name for output

Subject: Re: [xsl] How to get element name for output
From: "Eric Larson" <ionrock@xxxxxxxxx>
Date: Thu, 7 Jun 2007 09:36:19 -0500
There is also local-name() if for some reason you want to do get the
name without a namespace prefix. I could be misunderstanding how
local-name() works compared to name(), but hopefully someone else can
clarify if I am wrong about that.


On 6/6/07, Michael Kay <mike@xxxxxxxxxxxx> wrote:
You can get the name of a node using the XPath name() function, for example

<attribute type="{name()}"/>

Michael Kay

> -----Original Message----- > From: Chaudhary, Harsh [mailto:HCHAUDHA@xxxxxxxxx] > Sent: 06 June 2007 22:33 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] How to get element name for output > > Hi, > > I am writing XSLt (ver 1.0) for output to an XML file. At one > point I would like to get the name of the element and include > that in the output. An example would be: > > Input XML: > > <rootElement> > <productAttributeList> > <attributeMap> > <ReinstatementInProc>N</ReinstatementInProc> > </attributeMap> > <elementName>attribute</elementName> > </productAttributeList> > </rootElement> > > Output XML: > > <rootElement> > <attribute type="ReinstatementInProc">N</attribute> > </rootElement> > > I would really appreciate your help on this. > > Thanks, > Harsh.

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