Subject: Re: [xsl] replace|
From: "Charles Ohana" <charles.ohana@xxxxxxxxxxxxxx>
Date: Tue, 12 Jun 2007 10:10:41 -0400
I want to replace "a" by "b"
the code you posted, with Michael's change, would do that assuming teh EXSLT template is at the location implied by you rxsl:import.
inside "/root/@description" .
I suspect that you mean that you want to output the rest of the document unchanged, except for this change. XSLT will not do that automatically you neeed to add an "identity template" that copies each node from the input to the output. (google for modified identity tramsformation, or see examples in the faq or Jeni's site) the code you posted would just output the string value of the @description output, with the replacement made. In XSLT2 you don't need any replace templates, just select="replace(@description,'a','b') will do the job. Actually if you real example is a single letter you don't need anything other than select="translate(@description,'a','b') which would also work in xslt 1
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