Re: [xsl] node is in a nodelist?

Subject: Re: [xsl] node is in a nodelist?
From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx>
Date: Tue, 19 Jun 2007 06:23:49 -0700
On 6/19/07, Kai Hackemesser <kaha@xxxxxx> wrote:
I understand. But with key() as nodelist this is less performant than
David's solution, isn't it?

There are node-sets composed of nodes belonging to different documents (or even belonging to no document at all).

<xsl:key .../> only indexes the nodes of a single document  (at a
time) and the key() function returns a node-set of nodes, all
belonging to a single document.

Therefore, the expressions provided by Dr. Kay are more universal.

-- Cheers, Dimitre Novatchev --------------------------------------- Truly great madness cannot be achieved without significant intelligence. --------------------------------------- To invent, you need a good imagination and a pile of junk ------------------------------------- You've achieved success in your field when you don't know whether what you're doing is work or play

Ciao! kai

Michael Kay schrieb:
>> How do I know in a easy way if a node is in a nodelist (for
>> example returned by key())?
> In XSLT 2.0: exists($node intersect $nodelist)
> In 1.0: count($node | $nodelist) = count($nodelist)
> Michael Kay

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