Re: [xsl] node is in a nodelist?

["Dimitre Novatchev" <dnovatchev@xxxxxxxxx>]

On 6/19/07, Kai Hackemesser <kaha@xxxxxx> wrote:
> I understand. But with key() as nodelist this is less performant than
> David's solution, isn't it?



There are node-sets composed of nodes belonging to different documents
(or even belonging to no document at all).

<xsl:key .../> only indexes the nodes of a single document  (at a
time) and the key() function returns a node-set of nodes, all
belonging to a single document.

Therefore, the expressions provided by Dr. Kay are more universal.


--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
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To invent, you need a good imagination and a pile of junk
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You've achieved success in your field when you don't know whether what
you're doing is work or play



> Ciao!
> kai
>
>
>
> Michael Kay schrieb:
> >> How do I know in a easy way if a node is in a nodelist (for
> >> example returned by key())?
> >>
> >
> > In XSLT 2.0: exists($node intersect $nodelist)
> >
> > In 1.0: count($node | $nodelist) = count($nodelist)
> >
> > Michael Kay
> > http://www.saxonica.com/