RE: [xsl] [XSL]Display Different Results Based on Count of NodeSets

[Alice Ju-Hsuan Wei <ajwei@xxxxxxxxxxx>]

Hi,

  This is what I got for the output (I am actually using XSLT to 
transform into HTML, so the XML, as described previously, was that 
input)

  The output, oddly, when I used <xsl:value of select="count(title)"/> 
instead of position() it produced 2 and 1, respectively, but when the 
<xsl:apply-templates was inserted, it generates output of

  <div><p>Tennison, Jeni.</p>
  <p><i>Beginning XSLT</i>.</p>
   <p><i>Begining XSLT 2.0</i>.</p></div>

    <div><p>Meyer, Eric.</p>
    <p><i>The Zen of CSS</i>.</p>
     </div>

When I used the one I posted earlier:

<xsl:template match="title">
      <xsl:choose>
          <xsl:when test="position() ='1'"/>
          <xsl:otherwise>
              <p>
                  <xsl:apply-templates/>

              </p>
          </xsl:otherwise>
      </xsl:choose>
  </xsl:template>

It brings back the same input. However, I wanted the one on the first 
of the <title> to be something like:

    <div><p>Tennison, Jeni. <i>Beginning XSLT</i>.</p>
        <p><i>Begining XSLT 2.0</i>.</p></div>

     <div><p>Meyer, Eric. <i>The Zen of CSS.</i></p></div>


Is there some way I can do this?

Many thanks.

Alice