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Re: [xsl] xalan and replace "regex"

Subject: Re: [xsl] xalan and replace "regex"
From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx>
Date: Thu, 27 Dec 2007 09:10:37 +0000
>>>>> "Mansour" == Mansour  <mansour77@xxxxxxxxx> writes:

    Mansour> Hello: Is there any way I can use replace with xalan. I
    Mansour> have tried every thing possible but couldn't get it to
    Mansour> work:

No. It's not an XSLT 2.0 processor.
-- 
Colin Adams
Preston Lancashire
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