Re: [xsl] displaying a list in a multi-column table

["Andrew Welch" <andrew.j.welch@xxxxxxxxx>]

On 25/01/2008, Michael Tracey Zellmann <tracey.zellmann@xxxxxxxxx> wrote:
> I have a list of words, possibly 3500 to 7000 in length, in
> alphabetical order. I need to display them in an HTML page in a table
> of four columns. The first quarter of the words should be in the first
> column, the second quarter in the second column, etc. Since the total
> may not be divisible by four, the final column may be incomplete.
> Let's say the input is of the form:
> <wordList>
>   <word>aaron</word>
>   <word>abated</word>
>   <word>abatement</word>
>   ..
> </wordList>
>
> How can I do this with an XSLT transform?
>
> I can use XSLT 2.0

That's good... in which case you can do:

    <xsl:for-each-group select="$wordlist"
group-starting-with="*[position() mod 4 = 1]">
  	  <tr>
  	    <xsl:for-each select="current-group()">
  	      <td><xsl:value-of select="."/></td>	
  	    </xsl:for-each>
  	  </tr>    	
    </xsl:for-each-group>


cheers
-- 
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/