Re: [xsl] Copy Child Elements

Subject: Re: [xsl] Copy Child Elements
From: Alice Wei <ajwei@xxxxxxxxxxx>
Date: Fri, 25 Jan 2008 22:02:33 -0500

There is one obvious problem with your XSL here:

If you are using apply-templates, what it does is that it would select any of the children of the template root. Use <xsl:apply-templates select="section"> and and <xsl:apply-templates select="//section">

I am sure the others on the list would be able to help you with some of the other mistakes.

Good luck.


Quoting Rick Quatro <frameexpert@xxxxxxxxxxxx>:


Here is my input XML:

<?xml version="1.0" encoding="utf-8"?>
     <title>Author Job Title</title>
     <p id="Field_ShowAuthorJobTitle">Author Job Title</p>
     <p id="Desc_ShowAuthorJobTitle">Setting that indicates...</p>
     <p id="AppTo_ShowAuthorJobTitle">Review Definitions, Section Item</p>
     <p id="Hdr_ShowAuthorJobTitle">Author Settings</p>
     <title>Type (of definition)</title>
     <p id="Field_Typeofdefinition">Type (of definition)</p>
     <p id="Desc_Typeofdefinition">Type of the performance...
           <p><b>Focal</b>- A focal review is the most typical type...</p>
     <p id="AppTo_Typeofdefinition">Review Definitions, Section Item,
Performance Review</p>
     <p id="Hdr_Typeofdefinition">Properties</p>

Here is my desired output, except for the problem described below the output.

<?xml version="1.0"?>
 <dt>Author Job Title</dt>
 <dl>Setting that indicates...</dl>
 <dt>Type (of definition)</dt>
 <dl>Type of the performance... Focal- A focal review is the most
typical type...</dl>

For the <dt> and <dl> elements, I want to include any contents from
the original content; for example the <ul> element in the second
<section> element, etc.

Here is my stylesheet:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
 <xsl:output method="xml" />
 <xsl:template match="/">
     <xsl:apply-templates />

 <xsl:template match="reference">
   <xsl:apply-templates select="//section">
     <xsl:sort select="title" />

 <xsl:template match="section">
   <xsl:for-each select="p[position()&lt;=2]">
     <xsl:if test="position()=1">
         <xsl:apply-templates />
     <xsl:if test="position()=2">
         <xsl:apply-templates />


Any help is appreciated.

Rick Quatro
Carmen Publishing

Alice Wei MIS 2008 School of Library and Information Science Indiana University Bloomington ajwei@xxxxxxxxxxx

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