Subject: XSL to XSL? From: "Michael J. Hudson" <mhudson@xxxxxxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 05 Apr 2000 15:28:01 -0400 |
Here's what I'm currently doing. My task is to come up with a general way to transform any one XML file into another XML file with different DTDs. Now, what I'm doing is creating a tool that creates a mapping file that maps elements from one XML file to another. This is all fine and dandy. But now, I need to write an XSLT file that translates that XML mapping file into another XSLT script. That final XSLT script being the script that people would use to translate their XML files from one to another. The problem I'm having is getting an XSL script to output XSL elements. That is, I want the output to be another XSL file. The way I'm currently solving this, is using another namespace other than xsl.... say temp. So, that 'xsl:for-each' becomes 'temp:for-each'. And then I have a method that reads in the output file and does a find-replace changing temp back to xsl. Now, not being an expert in XSLT... I'm wondering if I'm bending over backwards to do this. Is there way in XSLT to have XSLT element outputs that don't affect the original XSLT file?? Thanks! ------------------------------------- Michael J. Hudson Software/Framework Engineer mhudson@xxxxxxxxxxxxxxxxx cell-phone: 703.932.6412 voice-mail: 703.827.0638 ext. 4786 fax: 703.734.0987 Blueprint Technologies "The E-Solution Architect" http://www.blueprinttech.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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