Re: [xsl] problem with Passing Parameters to Templates

["helen li" <helen_p_li@xxxxxxxxxxx>]

Also I have tried to use the following code to find and give the value of 
the element that is a descendant of the current node that is called 'codec'. 
It does not work either.

 <xsl:template name="opt_template">
     <xsl:param name="node"></xsl:param>
          <xsl:variable name="node-element"
                   select=".//*[local-name() = $node]" />
         <xsl:if test="$node-element">
           <xsl:value-of select="$node-element" />
         </xsl:if>
  </xsl:template>

Thanks,

Helen

> From: "helen li" <helen_p_li@xxxxxxxxxxx>
> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] problem with Passing Parameters to Templates
> Date: Mon, 22 Jan 2001 09:43:41 -0500
>
> Hi Jeni&David,
>
> Thanks for your help.
>
> What I really want to do is to output the value of element codec(not the
> value of variable $node) if the element codec exists.  With the following
> code, I did not get the result as expected. Did I do something wrong?
>
>  <xsl:template name="opt_template">
>      <xsl:param name="node"></xsl:param>
>          <xsl:if test=".//*[$node]">
>            <xsl:value-of select=".//*[name()=$node]"/>
>          </xsl:if>
>  </xsl:template>
>
>  <xsl:call-template name="opt_template">
>           <xsl:with-param name="node" select="'codec'"/>
>  </xsl:call-template>
>
> Thanks again,
>
> Helen
>
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