Subject: Re: [xsl] problem with Passing Parameters to Templates From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 22 Jan 2001 15:58:55 GMT |
<xsl:if test="$node-element"> <xsl:value-of select="$node-element" /> </xsl:if> again, a spurious if. You _never_ need do that. The above is equivalent to <xsl:value-of select="$node-element" /> <xsl:template name="opt_template"> <xsl:param name="node"></xsl:param> <xsl:variable name="node-element" select=".//*[local-name() = $node]" /> <xsl:if test="$node-element"> <xsl:value-of select="$node-element" /> </xsl:if> </xsl:template> is just <xsl:template name="opt_template"> <xsl:param name="node"/> <xsl:value-of select=".//*[local-name() = $node]" /> </xsl:template> David XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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