Subject: Re: [xsl] XSL rule for sorting the elements in descending order and display ing the first element in sorted list From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx> Date: Thu, 15 Feb 2001 09:29:49 +0000 |
Hi Anand, > i wanto to sort it in descending order and display the first element after > sorting ... i.e. to output the maximum of the list. To sort you need the xsl:sort element. The xsl:sort element has to go within something that iterates over a node set, such as an xsl:for-each. To select the first item, you need an xsl:if. You can test the position() of the item in the node list. If it's equal to 1 then it's the first item. Putting that together, you get: <xsl:template match="JartaXmlReport"> <xsl:for-each select="SessionStartupTime"> <xsl:sort data-type="number" order="descending" /> <xsl:if test="position() = 1"> <xsl:value-of select="." /> </xsl:if> </xs:for-each> </xsl:template> I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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