Re: [xsl] outputing a non existant element.

[Jörg Heinicke <joerg.heinicke@xxxxxx>]

Hi,

what about this snippet:

<xsl:choose>
    <xsl:when test="fruit">
        <xsl:value-of select="fruit"/>
    </xsl:when>
    <xsl:otherwise>
        <xsl:text>apple</xsl:text>
    </xsl:otherwise>
</xsl:choose>

Getting the value out of the schema-file is not possible I think.

I know something about a default-value of an attribute. If the attribute is
not specified the XSLT-processor returns this default-value. But I heard,
this behaviour is not specified too. It works in Xalan.

Joerg

----- Original Message -----
From: "Auguste Oumar" <oumar_a@xxxxxxxx>
To: <XSL-List@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Wednesday, September 12, 2001 7:17 PM
Subject: [xsl] outputing a non existant element.


> Hi,
> i have one optional element in my schema-file say:
> <fruit>orange</fruit>.The default value of fruit is
> "apple".I would like to have a xslt-transformation
> which gives me the content of the fruit element if it
> appears in the xml-file or its default value if it
> doesn't appear.I have problem giving out the default
> value when the element doesn't appear in the
> xml-file.How can i solve it ?
>
> Thanks for help.
>
> Auguste


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