[xsl] getting associated file name for element

Subject: [xsl] getting associated file name for element
From: "Matthew L. Avizinis" <mla@xxxxxxxxx>
Date: Wed, 6 Mar 2002 16:14:36 -0500
Hello all,
  If I am doing something like:

    <xsl:for-each select="document($all-questions//quiz/@href)//question">
        <xsl:sort order="ascending" select="faa-num"/>
      ...do stuff with each question...
         <xsl:value-of select="faa-num"/>
         Here's where I want to grab the name of the file, i.e. @href, the
question came from

where quiz/@href contains the filenames containing questions to be grabbed
and then sorted by a question child element called faa-num.
How can I grab the value of @href as each question is evaluated?

So, in other words $all-questions was obtained by a document() reference to
an xml file with a bunch of <quiz> elements each with a @href child which
contains the paths to xml files which then contain all the <questions>s.
Using the scenario above how can I grab the @href value as each question is
processed, that is the name of the file each question is contained in.

thanks for all help with this,
   Matthew L. Avizinis <mailto:mla@xxxxxxxxx>
Gleim Publications, Inc.
   4201 NW 95th Blvd.
 Gainesville, FL 32606
(352)-375-0772 ext. 101
      www.gleim.com <http://www.gleim.com>

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