Subject: [xsl] Variable containing tree From: "Filipe Correia" <filipe.correia@xxxxxxxxxxxxxxx> Date: Fri, 07 Jun 2002 09:49:17 +0100 |
Hi, I'm assigning a set of nodes to a variable like this: <xsl:variable name="var"> <xsl:apply-templates/> </xsl:variable> wich I would like to output later on only if the variable is not empty. I've tried outputing it like this: <xsl:if test="$restFormElements != '' "> <result> <xsl:apply-templates select="$restFormElements"/> </result> </xsl:if> but the test is never true. I'm not sure how to test this... But beyond the test part... If I just try to output my variable: <xsl:apply-templates select="$restFormElements"/> xalan exits with an exception: "Can not convert #RTREEFRAG to a NodeList!" so I tried to convert the tree fragmente to a node list using xalan's built in "nodeset()" function. like this: <xsl:apply-templates select="xalan:nodeset($restFormElements)"/> but I only get the the resulting tree's root node... and not the entire tree as I was expecting. How is this behavior explained? thks in advance! Filipe XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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