Re: [xsl] sorting by position?

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

<xsl:for-each select="row">
  <xsl:sort select="column[$sortcol]"/>
  <!-- rows sorted by the $sortcol'th <column/> -->
</xsl:for-each>

Regards,

Joerg

Stuart Zakon wrote:
> Is there any way to sort using <xsl:sort> for a positional sort?
> For instance, given the following XML for a generic table, is there
> a way to specify to sort the rows by the first or second column, depending
> on which column is chosen to sort by?
>
> <?xml version="1.0" encoding="ISO-8859-1"?>
> <table>   
>     <row>
>         <column>x</column>
>         <column>b</column>
>     </row>
>     <row>
>         <column>z</column>
>         <column>c</column>
>     </row>
>     <row>
>         <column>y</column>
>         <column>a</column>
>     </row>
> </table>
>
>
> Thanks,
> Stuart Zakon
> Objects by Design


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