Subject: RE: [xsl] Design question From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Wed, 10 Jul 2002 09:09:04 +0100 |
> I'm attempting to use XSL to transform XML to XML. The > problem is that > some child elements in the original XML are "attributes" of > the new XML > element, whereas other child "elements" are actually new > child elements. > That is: > > BEFORE: > <test type="positive" name="Test 1"> > <param name="p1">123</param> > <param name="date1">July 9</param> > <param name="p2">false</param> > </test> > > AFTER: > <da:Positive name="Test 1" p1="123" p2="false"> > <da:Date number="1" value="July 9"/> > </da:Positive> > > (Notice that p1 and p2 become attributes of the new element, > but date1 > becomes a new child element.) > > From what I can tell, I need to accomplish the equivalent of the > following, but haven't been able to come up with the way to do it: > > (1) Iterate through all original <param>s. For each <param> that will > become an attribute, do <xsl:attribute>. For each <param> > that will become > a child element, store it off to the side in a node set of some sort. > > (2) When the iteration is complete, iterate through the node > set built in > (1), and do <xsl:element> on each. > A simpler approach is to iterate through the original params twice; the first time, select those that will become attributes, the second time, select those that will become child elements. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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