Subject: RE: [xsl] Design question From: Jay Burgess <jburgess@xxxxxxxxxxx> Date: Wed, 10 Jul 2002 09:51:41 -0500 |
> -----Original Message----- > From: Jay Burgess [mailto:jburgess@xxxxxxxxxxx] > Sent: Tuesday, July 09, 2002 5:13 PM > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Design question > > > I'm attempting to use XSL to transform XML to XML. The > problem is that > some child elements in the original XML are "attributes" of > the new XML > element, whereas other child "elements" are actually new > child elements. > That is: > > BEFORE: > <test type="positive" name="Test 1"> > <param name="p1">123</param> > <param name="date1">July 9</param> > <param name="p2">false</param> > </test> > > AFTER: > <da:Positive name="Test 1" p1="123" p2="false"> > <da:Date number="1" value="July 9"/> > </da:Positive> > > (Notice that p1 and p2 become attributes of the new element, > but date1 > becomes a new child element.) > > From what I can tell, I need to accomplish the equivalent of the > following, but haven't been able to come up with the way to do it: > > (1) Iterate through all original <param>s. For each <param> that will > become an attribute, do <xsl:attribute>. For each <param> > that will become > a child element, store it off to the side in a node set of some sort. > > (2) When the iteration is complete, iterate through the node > set built in > (1), and do <xsl:element> on each. > > Is this the right way to solve this problem? If so, can > someone provide > some more detail, as nothing I've tried has worked. Or, is > there a better way? > > Thanks in advance. > > Jay > > -- Jay Burgess [jburgess@xxxxxxxxxxx] > Digital Archaeology Corporation > (913) 438-9444 x154 >
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] Design question, Michael Kay | Thread | [xsl] XPath Explorer Release 200207, guru |
Re: [xsl] Urgent: Load a document i, David Carlisle | Date | RE: [xsl] key() question?, TSchutzerWeissmann |
Month |