Subject: [xsl] selecting all nodes which contains similar names From: "Braumüller, Hans" <h.braumueller@xxxxxxxxxxxx> Date: Fri, 26 Jul 2002 12:50:19 +0200 |
Hi, i know this is a FAQ, but i cannot find it with google and in the archive. I want to extract with a shortest statement all nodes which begins with the same characters in the element . xml snippet ---- <row> ... <umszweck1>UMSZWECK1</umszweck1> <umszweck2>UMSZWECK2</umszweck2> <umszweck3>UMSZWECK3</umszweck3> <umszweck4>UMSZWECK4</umszweck4> <umszweck5>UMSZWECK5</umszweck5> <umszweck6></umszweck6> <umszweck7>UMSZWECK7</umszweck7> <umszweck8>UMSZWECK8</umszweck8> <umszweck9>UMSZWECK9</umszweck9> <umszweck10></umszweck10> <umszweck11>UMSZWECK11</umszweck11> <umszweck12>UMSZWECK12</umszweck12> <umszweck13>UMSZWECK13</umszweck13> <umszweck14>UMSZWECK14</umszweck14> etc ... </row> xsl try ---- <xsl:-for each select="node()[contains(name(),'umszweck')]"> <xsl:value-of select="." /> </xsl:for-each> It´s not function! Must i do a when=test()? It is possible instead using a template? Anybody can forward me a code snippet? Excuse my still a beginner question! Have a nice weekend! Thanks, Hans Braumüller -- + -- Networking Artist http://crosses.net http://kunstserie.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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