Subject: RE: [xsl] selecting all nodes which contains similar names From: Jarno.Elovirta@xxxxxxxxx Date: Fri, 26 Jul 2002 14:12:22 +0300 |
Hi, > i know this is a FAQ, but i cannot find it with google and in > the archive. Did you check the XPath 1.0 spec <http://www.w3.org/TR/xpath#section-String-Functions>? > I want to extract with a shortest statement all nodes which > begins with the > same characters in the element . > > xml snippet > ---- > > <row> > ... > <umszweck1>UMSZWECK1</umszweck1> > <umszweck2>UMSZWECK2</umszweck2> > <umszweck3>UMSZWECK3</umszweck3> > <umszweck4>UMSZWECK4</umszweck4> > <umszweck5>UMSZWECK5</umszweck5> > <umszweck6></umszweck6> > <umszweck7>UMSZWECK7</umszweck7> > <umszweck8>UMSZWECK8</umszweck8> > <umszweck9>UMSZWECK9</umszweck9> > <umszweck10></umszweck10> > <umszweck11>UMSZWECK11</umszweck11> > <umszweck12>UMSZWECK12</umszweck12> > <umszweck13>UMSZWECK13</umszweck13> > <umszweck14>UMSZWECK14</umszweck14> > etc > ... > </row> > > xsl try > ---- > <xsl:-for each select="node()[contains(name(),'umszweck')]"> > <xsl:value-of select="." /> > </xsl:for-each> <xsl:-for each select="*[start-with(name(), 'umszweck')]"> Cheers, Jarno XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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