RE: [xsl] selecting all nodes which contains similar names

Subject: RE: [xsl] selecting all nodes which contains similar names
From: Jarno.Elovirta@xxxxxxxxx
Date: Fri, 26 Jul 2002 14:12:22 +0300
Hi,

> i know this is a FAQ, but i cannot find it with google and in 
> the archive.

Did you check the XPath 1.0 spec <http://www.w3.org/TR/xpath#section-String-Functions>?

> I want to extract with a shortest statement all nodes which 
> begins with the
> same characters in the element .
> 
> xml snippet
> ----
> 
> <row>
> ...
> <umszweck1>UMSZWECK1</umszweck1>
> <umszweck2>UMSZWECK2</umszweck2>
> <umszweck3>UMSZWECK3</umszweck3>
> <umszweck4>UMSZWECK4</umszweck4>
> <umszweck5>UMSZWECK5</umszweck5>
> <umszweck6></umszweck6>
> <umszweck7>UMSZWECK7</umszweck7>
> <umszweck8>UMSZWECK8</umszweck8>
> <umszweck9>UMSZWECK9</umszweck9>
> <umszweck10></umszweck10>
> <umszweck11>UMSZWECK11</umszweck11>
> <umszweck12>UMSZWECK12</umszweck12>
> <umszweck13>UMSZWECK13</umszweck13>
> <umszweck14>UMSZWECK14</umszweck14>
> etc
> ...
> </row>
> 
> xsl try
> ----
> <xsl:-for each select="node()[contains(name(),'umszweck')]">
>  <xsl:value-of select="." />
> </xsl:for-each>

<xsl:-for each select="*[start-with(name(), 'umszweck')]">

Cheers,

Jarno

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