Subject: Re: [xsl] math get maximum and subtract 1 From: "sascha" <sascha@xxxxxxxxxx> Date: Wed, 31 Jul 2002 12:54:41 +0200 |
Yes, i thought so, but HOW? please help. I'm a little confused. Perhaps I have to sit back and think this over I have 5 rows with 2 columns - each column consists of a VALUE and a LABEL which i put in another TABLE within the current cell (called by a template) How do I have to go through the for-each loops..?. mhm... I wish there were "for x = 1 to $max" loops. Sascha > Yes; it looks like they're sorting it by row first now, rather than by > column. That's great, since it still means that the last > DESCRIPTION_ITEM in the DESCRIPTION_TABLE has the maximum row/col, so > you can still use: > > <xsl:variable name="nrow" > select="/DESCRIPTION_TABLE/DESCRIPTION_ITEM[last()]/@row" /> > > <xsl:variable name="ncol" > select="/DESCRIPTION_TABLE/DESCRIPTION_ITEM[last()]/@col" /> > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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