Subject: Re: [xsl] transforming XML into XML using XSLT. From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Tue, 13 Aug 2002 17:44:12 -0400 |
Is it possible to convert XML[having useful +unnecessary data ] -----to-----> XML [having Useful data] using XSLT.Could you please help me out with an example.
<source> <useful>This is an example on XSL-List</useful> <unnecessary>It's rather pointed (unnecessarily so).</unnecessary> </source>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<!-- this could be a near-identity transform, but for ease of illustration we'll just strip out the node structure instead -->
<xsl:template match="/"> <result> <!-- this template is here so the result is actually XML, rather than simply a well-formed external parsed entity --> <xsl:apply-templates/> </result> </xsl:template>
Cheers, Wendell
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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