Subject: Re: [xsl] transforming XML into XML using XSLT. From: "J.Pietschmann" <j3322ptm@xxxxxxxx> Date: Wed, 14 Aug 2002 00:03:22 +0200 |
Thank you. Please find below the Input XML file , Required Output XML file and the XSLT I had developed.
... You can start with the generic copy-through template and define templates for lements you want to get rid of as no-ops:
<?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output type="xml"/> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template> <xsl:template match="country"/> <xsl:template match="company"/> <xsl:template match="price"/> <xsl:template match="year"/> </xsl:stylesheet>
I don't have an exclusive processor , I am viewing the output in Internet explorer 5.5.
That'd be a problem, because the browser will interpret the generated XML as HTML.
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