Subject: Re: [xsl] Outputting from more than one source From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Sun, 13 Oct 2002 22:51:49 +0200 |
Joerg: It brings the same, even with this variable. I'm using MSXML 4.0 (IE6) and Mozilla. In both the result is the same. Do you have another suggestion?
Liao: I could change the Java code to produce only one document. But I don't want to change the specification of my project. Just for the record, this project is a parcial requisite for my graduation. Let's say I'll change my Jave code as a last option.
----- Original Message ----- From: "Joerg Heinicke" <joerg.heinicke@xxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Sunday, October 13, 2002 7:39 AM Subject: Re: [xsl] Outputting from more than one source
1stHmm, it should work - at least it looks ok. What processor are you using? What happens if you do it in the following way:
<xsl:variable name="reg" select="/clients_ora/reg | document('other.xml')/clients_sqlsrv/reg | document('another.xml')/clients_db2/reg"/>
<xsl:apply-templates select="$reg"> <xsl:sort select="name"/> </xsl:apply-templates>
Regards,
Joerg
Gustavo Moreira wrote:
Yes, but what if there are three or more documents?
This, for instance, would this work?:
xsl:apply-templates select="/clients_ora/reg | document('other.xml')/clients_sqlsrv/reg | document('another.xml')/clients_db2/reg"> <xsl:sort select="name"/> </xsl:apply-templates>
I am using this:
<xsl:apply-templates select="document('clients_sqlsrv.xml')//clients_sqlsrv/reg | document('clients_ora.xml')//clients_ora/reg"> <xsl:sort select="name"/> </xsl:apply-templates>
...and it doesn't work because it brings first all the clients from the
theyfile (ordered), then it follows with all the clients from the 2nd file (ordered). What I want is all clients from all files ordered, no matter what file
come from.
Gustavo Moreira
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