Subject: Re: [xsl] XML reformatting <xsl:element & <xsl:for-each From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Tue, 7 Jan 2003 14:41:19 +0000 |
Hi Alan, > I'm trying to use the <xsl:element> in the template for the <Table> > section and loop through all the child nodes of <Table> to put them > in the output xml, but It keeps saying that the element name is not > a QName, How can I accomplish this??? You're trying to create the element name dynamically, from a function, so the name attribute of <xsl:element> should be an attribute value template: put {}s around the function call. Rather than: > <xsl:element name="name()"> > <xsl:value-of select="current()/text()"/> > </xsl:element> use: <xsl:element name="{name()}"> <xsl:value-of select="." /> </xsl:element> or, better, since you're just copying an existing element, use xsl:copy: <xsl:copy> <xsl:value-of select="." /> </xsl:copy> or, since none of your elements have child elements, this is equivalent to: <xsl:copy-of select="." /> > I'm also getting Odd errors about <xsl:text>, 'Unexpected Child'. In XSLT 1.0, <xsl:text> can't have children. Rather than: > <xsl:text> > <xsl:value-of select="current()/text()"/> > </xsl:text> you should use just: <xsl:value-of select="current()/text()" /> or even just: <xsl:value-of select="." /> I think that the easiest way to create your output is to just copy all the element children of the <Table> element directly using <xsl:copy-of>. For example, you could do your transformation with: <xsl:template match="NewDataSet"> <data> <xsl:copy-of select="Table/*" /> <fabrics> <xsl:copy-of select="Table1/FabricId" /> </fabrics> <attributes> <xsl:for-each select="Table2"> <attribute id="{Attributeid}"> <xsl:value-of select="Setting" /> </attribute> </xsl:for-each> </attributes> </data> </xsl:template> Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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