AW: [xsl] how to "save" a context?

["Braumüller, Hans" <H.Braumueller@xxxxxxxxxxxx>]

Ho Dimitri,

i tried to do it with msxml3 and 4

<?xml version="1.0"  encoding="ISO-8859-1" ?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<root>
  <test>xpath</test>
</root>


and 

<xsl:stylesheet version='1.0'
xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>

<xsl:output method="text" />

..... (nothing changed)

<xsl:value-of select="$theResult"/>

and get as result

ÿþ

Never mind, which xsml-source i use, i get the same.

What i do wrong ?

Thanks,

Hans Braumüller

"S Woodside" <sbwoodside@xxxxxxxxx> wrote in message
news:1D578741-27F8-11D7-AD3E-000393414368@xxxxxxxxxxxx
> Gah! It's huge!
> 
> Seriously it looks like this will generate a string that, when
assigned 
> to a variable, and selected upon, will act as the correct XPath. Is 
> that right?

Yes, actually this snippet processes a nodeset of nodes and generates a
set of strings (XPath expressions) for each of them. You can simplify
it a bit to work only on a single node (get rid of the outermost
xsl:for-each).

> 
> It has:  <xsl:value-of select="msxsl:node-set($theResult)"/>
> 
> Does it require MSxml? Can I turn $theResult (which is a string, 
> right?) into an XPath expression I can use in a select statement, 
> without needing MSXML?

Actually, the xxx:node-set extension function is not required.

Just get rid of it and the msxsl namespace, too.




=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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