Re: AW: [xsl] how to "save" a context?

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

--- <H.Braumueller@xxxxxxxxxxxx> wrote:
> Ho Dimitri,
> 
> i tried to do it with msxml3 and 4
> 
> <?xml version="1.0"  encoding="ISO-8859-1" ?>
> <?xml-stylesheet type="text/xsl" href="test.xsl"?>
> <root>
>   <test>xpath</test>
> </root>
> 
> 
> and 
> 
> <xsl:stylesheet version='1.0'
> xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>
> 
> <xsl:output method="text" />
> 
> ...... (nothing changed)
> 
> <xsl:value-of select="$theResult"/>
> 
> and get as result
> 
> ÿþ
> 
> Never mind, which xsml-source i use, i get the same.
> 
> What i do wrong ?


Hans,

This snippet uses the following xsl:param

  <xsl:variable name="theParmNodes" select="$some-NodeSet"/>

You have to modify the "select" attribute above and to set it to the
node(s) for which you want their XPath expressions produced.




=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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