Subject: [xsl] Finding the path from the filename From: "Thomas V. Nielsen" <thomas@xxxxxxxxxxxxx> Date: Mon, 20 Jan 2003 16:18:08 +0100 |
In a XSLT I receive a parameter with a full path and file name, like; C:\Data\Test\File.xml I have tried fumbling with substring and substring-before, but with no luck. What I need is the full path without the file name, like C:\Data\Test\ Sometimes parameter looks like this ..\Test\File.xml And also here I need to find the path, like ..\Test\ Any suggestions in how to use the substring with some iteration? /Thomas XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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