Subject: [xsl] xsl:if problem From: "Craig Wehr (ns)" <CWehr@xxxxxxx> Date: Thu, 13 Mar 2003 14:14:32 -0600 |
I am having a problem with xsl:if not working properly. This is what I want to do: if there is content in the "BlockBody" node in the XML file, everything is output to the file. if there is no content in the "BlockBody" node in the XML file, the xsl skips the BlockBody output, yet outputs the <HR> and <A> link. ex: <xsl:template match="BlockBody"> <xsl:if test="BlockBody!=''"> <p><xsl:text>Policy</xsl:text></p> <p><xsl:apply-templates/></p> </xsl:if> <hr></hr> <p><a href="index.html" class="bodyLink">[Table of Contents]</a></p> </xsl:template> I'm not sure if <xsl:if test="BlockBody!=''"> is valid. can anyone help me make this work? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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