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[xsl] match attribute values

Subject: [xsl] match attribute values
From: "Mac Martine" <email@xxxxxxxxxxxxxxxx>
Date: Thu, 27 Mar 2003 13:08:03 -0800
Hello-
 I am trying to find all values of a specified attribute and sort them
in order. I know this is normally really easy, but I add one complicated
factor. Sometimes the attribute will have multiple values separated by a
','. I am assigning certain elements a task number, but some elements
will have multiple task numbers. So I need to go through and find which
elements holds the certain value that I am looking for. I am only
supplying the stripped code for the issue I am having (I have not
included the string splitting code, etc). With the code below I get a
recursion error. So, I basically need to find the element where @task =
1, then where @task = 2, @task = 3 and so on. So, any help would be
appreciated, or any more clever approaches than what I am attempting
here. Thanks-
 Mac



<?xml version="1.0"?>

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:template match="/">
        <body>
        <table width="80%">
                <xsl:apply-templates select="//*[@task = 1]">
                        <xsl:with-param name="nextTask" select="1"/>
                </xsl:apply-templates>
        </table>
        </body>
</xsl:template>

<xsl:template match="*">
        <xsl:param name="nextTask"/>

        <br />
        -->> @TASK = <xsl:value-of select="@task" /> : $NEXTTASK =
<xsl:value-of select="$nextTask" />

        <xsl:if test="@task = $nextTask">
                (<xsl:value-of select="local-name()" />)
        </xsl:if>

        <xsl:apply-templates select="//*[@task=2]">
                <xsl:with-param name="nextTask" select="2"/>
        </xsl:apply-templates>
</xsl:template>

</xsl:stylesheet>



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