RE: [xsl] Parameterized sort

["Michael Kay" <mhk@xxxxxxxxx>]

You've got your knickers in a twist. You want

<xsl:sort select="column[@name=$sortByColumn]"/>

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 


> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Kim Tran
> Sent: 01 April 2003 14:25
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Parameterized sort
> 
> 
> I have the following sort problem where I want to have the 
> sort key defined 
> as a parameter.
> 
> For example, here is my XML:
> <document>
> <row><column name="FirstName">John</column>
>       <column name="LastName">Doo</column>
> </row>
> <row><column name="FirstName">Alice</column>
>       <column name="LastName">Mulcaster</column>
> </row>
> 
> I want to sort the list by either FirstName or LastName.  
> Here is my xsl 
> file:
> 
> <?xml version="1.0" encoding="ISO-8859-1"?>
> <xsl:stylesheet
>   xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>   version="1.0" xmlns:xalan="http://xml.apache.org/xalan";>
> <xsl:output method="xml"/>
> 
> <xsl:param name="sortByColumn" select="'FirstName'"/> 
> <xsl:template match="/"> <Document> <xsl:for-each 
> select="Document/row"> <xsl:sort 
> select="column[@name=*[name()=$sortByColumn]]"/>
> <row>
>   <xsl:apply-templates select="column"/>
> </row>
> </xsl:for-each>
> </Document>
> </xsl:template>
> 
> <xsl:template match="column">
> <xsl:copy-of select="."/>
> </xsl:template>
> </xsl:stylesheet>
> 
> However, it still doesn't work.  I know that the sort key if 
> defined as 
> parameter, I should use "xalan:evalue($sortKey)" or "*[name() 
> = $sortKey]".  
> In this case, I want to sort the rows by the FirstName column 
> or by LastName 
> column and First Name.
> 
> If I say,
> <xsl:sort select="column[@name='FirstName']"/>
> then, it works properly.
> 
> Many thanks in advance.
> 
> 
> 
> 
> 
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