Re: [xsl] XSL to XSLT conversion issue

[S Woodside <sbwoodside@xxxxxxxxx>]

On Tuesday, April 15, 2003, at 03:20  PM, Jim Hart wrote:

> I want to convert:
>
> [ index() $gt$ context()!index() ]
>
> to something equivalent in XSLT. In MSXML docs, it says that context() 
> is equivalent to context(-1). At topxml it says that current() in XSLT 
> is equivalent to context(-1) in XSL. I know I can use > in place of 
> $gt$ and position() in place of index(). However, there's no 
> equivalent for the "bang operator" (!) and position() won't take an 
> argument. So, I can't figure out how to get the position() of 
> current().

What is this supposed to do? > or > or < will also work as 
operators. What did the bang do in MSXSL? There certainly is a bang in 
XSLT, as in != (not equals).

As far as getting the position() from current() (the XSLT context 
rather than the XPath context) not sure how you'd do that. You may need 
to refactor, it certainly should be doable. I don't suppose 
current()/position() works?

simon

>

--
www.simonwoodside.com -- 99% Devil, 1% Angel


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