Re: [xsl] Looping in XSLT(old question, but maybe new problem)

[Mike Brown <mike@xxxxxxxx>]

Liu Shuai wrote:
> Hi, all
> 
> I am trying to write a template that will generate a table based on a xml
> file and right now I don't have any
> clue how to do it.
> 
> If I have a source file looks like this
> 
> <foo>
> 	<bar id='1'>
> 		<someElement>a</someElement>
> 	</bar>
> 	<bar id='2'>
> 		<someElement>b</someElement>
> 	</bar>
> 	<bar id='3'>
> 		<someElement>c</someElement>
> 	</bar>
> 	<bar id='4'>
> 		<someElement>d</someElement>
> 	</bar>
> 	<bar id='5'>
> 		<someElement>e</someElement>
> 	</bar>
> 	...
> </foo>
> 
> Can I write a style sheet that will transform the source file above to a
> html table like this?
> 
> <table>
> 	<tr>
> 		<td>a</td>
> 		<td>b</td>
> 		<td>c</td>
> 	</tr>
> 	<tr>
> 		<td>d</td>
> 		<td>e</td>
> 		<td>&nbsp;</td>
> 	</tr>
> 	...
> </table>
> 
> Basicly, I want to generate N columns per row but I don't know how many
> "bar"s I have in the source file.

Select all bar elements for processing.
In the template that matches a bar element, if position() returns
a value that when divided by 3 has a remainder of 1, generate a table row
element. Inside that element, create cells for the current node and its
first two following siblings.


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