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Subject: [xsl] as efficient as possible... From: "Corey Wilson" <corey@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 2 Jul 2003 13:06:27 -0400 |
XML
---
<earners>
<earner>
<id />
<name />
</earner>
</earners>
<clients>
<client>
<id>
<name>
<commissions>
<commission>
<id />
<earnerId />
<product>
<productId />
<rate />
</prodcut>
</commission>
</commissions>
<products>
<product>
<id />
<name />
</product>
</products>
</client>
</clients>
XSL
---
./products/product[id=../../commissions/commission[earnerId=$earnerId]/produ
ct/productId]
Problem
-------
I am trying to get a list of the products that are listed in the <products>
node that are also in the <commission/product> node... The way I have above
works.. but it seems to be very slow... I am working with a large amount of
data... but I was curious if there was a better way? $earnerId would be
the current earner I am trying to calculate totals for... Thanks very much
for any help!!
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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