Subject: [xsl] as efficient as possible... From: "Corey Wilson" <corey@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 2 Jul 2003 13:06:27 -0400 |
XML --- <earners> <earner> <id /> <name /> </earner> </earners> <clients> <client> <id> <name> <commissions> <commission> <id /> <earnerId /> <product> <productId /> <rate /> </prodcut> </commission> </commissions> <products> <product> <id /> <name /> </product> </products> </client> </clients> XSL --- ./products/product[id=../../commissions/commission[earnerId=$earnerId]/produ ct/productId] Problem ------- I am trying to get a list of the products that are listed in the <products> node that are also in the <commission/product> node... The way I have above works.. but it seems to be very slow... I am working with a large amount of data... but I was curious if there was a better way? $earnerId would be the current earner I am trying to calculate totals for... Thanks very much for any help!! XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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