RE: [xsl] Using not(...a nd ... ) to select nodes

[cknell@xxxxxxxxxx]

You say that each "item" node has three child nodes, yet your list of items shows four values for each item. Which is correct?
-- 
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     "Barak" <barak@xxxxxxxxxxx>
Sent:     Thu, 10 Jul 2003 15:43:01 -0400
To:       <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject:  [xsl] Using not(...a nd ... ) to select nodes

Hello!

I'm fairly new to XSLT and have been trhown in the deep end here.  :p

I have a problem I've been beating my head against a wall over for a
couple of days, so now that it's good and bloody I've found this mailing
list.  

In a nutshell, I have "item" nodes that have three sub nodes: name, type
and status. 

I'm trying to create a node set that only contains different nodes.  The
problem I'm running into is I seem to be losing nodes that I shouldn't.

I'm using the following to select the nodes:

<xsl:for-each select="items/item[not(name = preceding-sibling::*/name
and type = preceding-sibling::*/type and status  preceding-sibling::*/status)]">		


An example from the XML might be: truck,silverado,chevy,on
truck,silverado,chevy,off truck,ranger,ford,on 	truck,silverado,chevy,on
truck,silverado,chevy,off

>From that I want to see the first three in a node set.  However, what
I'm getting are the second and third ones.
	
Any suggestions would be much appreciated.

Chris



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