| Subject: Re: [xsl] newbie needs help From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Thu, 11 Sep 2003 16:00:40 -0400 | 
Not all documents in the source xml file contain links and I want the output xml to only contain documents that have links. How can the template below be changed to only output documents that contain links.
<xsl:template match="document"> <document> <xsl:copy-of select="form|.//link"/> </document> </xsl:template>
<xsl:template match="document[.//link]"> <document> <xsl:copy-of select="form|.//link"/> </document> </xsl:template>
<xsl:template match="document">
  <xsl:if test=".//link">
   <document>
      <xsl:copy-of select="form|.//link"/>
    </document>
  </xsl:if>
</xsl:template>Cheers, Wendell
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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