Re: [xsl] Count() nodes ??

Subject: Re: [xsl] Count() nodes ??
From: Koteswararao Mogili <raomvk@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 16 Sep 2003 12:02:36 -0400
try this too count(//Root/FixedNodes/Node[@name=1]/*)
On Tuesday, September 16, 2003, at 11:41 AM, xsl-list@xxxxxxxxxxxxxxxxxxxxxx wrote:

did u try count(//Root/FixedNodes/Node[@name=1])


--Rao On Tuesday, September 16, 2003, at 11:24 AM, xsl-list@xxxxxxxxxxxxxxxxxxxxxx wrote:

Hi,

I am having the following xml document.

<Root>
 <FixedNodes>
   <Node name="1">
      <Subnode myAtt="itsValue"/>
      <Subnode myAtt="itsValue"/>
      <Subnode myAtt="itsValue"/>
   </Node>
   <Node name="2">
       <Subnode myAtt="itsValue">
       <Subnode myAtt="itsValue">
       <Subnode myAtt="itsValue">
       <Subnode myAtt="itsValue">
    </Node>
 </FixedNodes>
 <VaryingNodes>
     <Node name="3">
       <Subnode myAtt="itsValue">
       <Subnode myAtt="itsValue">
     </Node>
  </VaryingNodes>
</Root>

How do i count number of Subnode within FixedNodes.
I tried using
"count(//Root/FixedNodes/Node/Subnode)
But i got count as zero. Is this because there is attribute associated
with
each of the Node element ?


Can someone please tell me how do i count it ?
Thanks in the anticipation that I will get some reply.

Regards,
Dipesh


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