Subject: RE: [xsl] Getting a distinct list of node names From: "Andreas L. Delmelle" <a_l.delmelle@xxxxxxxxxx> Date: Mon, 15 Dec 2003 21:04:50 +0100 |
> -----Original Message----- > From: Manuel Holtgrewe > > I need to get a distinct list of the node names from all children of one > node. For example, if I have: > > <node:definition> > <form:validator /> > <form:validator /> > <form:filter /> > </node:definition> > tricky one... I tried it like: <xsl:template match="node:definition"> <xsl:for-each select="*[name(.) != preceding::*]"> <xsl:if test="position() = 1"> <xsl:text>('</xsl:text> </xsl:if> <xsl:value-of select="name()" /> <xsl:text>'</xsl:text> <xsl:choose> <xsl:when test="position() != last()"> <xsl:text>, </xsl:text> </xsl:when> <xsl:otherwise> <xsl:text>)</xsl:text> </xsl:otherwise> </xsl:choose> </xsl:for-each> </xsl:template> Provided you include the namespace declaration for the node:* namespace in your XSL, there shouldn't be any problems... Could get expensive with long lists maybe. Cheers, Andreas XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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