RE: [xsl] Output XML just as it is...

[Jarno.Elovirta@xxxxxxxxx]

Hi,

> <campaign>
>     <table width="100%">
>         <tr><td colspan="2">You say Yes</td></tr>
>         <tr><td>I say no</td>
>         <td>You say goodbye</td></tr>
>     </table>
>     <img src="/images/some_image.gif"/>
> </campaign>
> 
> I am trying to implement this from XSL like this:
> 
> <xsl:template match="/">
>     <!-- reference external xml/xhtml source-->
>         <xsl:variable name="c"
> select="document('../campaigns/simpleone.xml')//campaign"/>
>         <xsl:value-of disable-output-escaping="yes" select="$c"/>
> </xsl:template>
> 
> ( Returned raw text... HTML stripped )

You want xsl:copy-of instead of xsl:value-of.
 
> Then I tried something like this
> 
> <xsl:template name="PREVIEW">
>     <xsl:variable name="c" 
> select="document('../campaigns/simpleone.xml')"/>
>     <xsl:apply-templates select="$c"/>
> </xsl:template>
> 
> <xsl:template match="*">
>  <xsl:value-of select="."/>
> </xsl:template>
> 
> ( However, could not come up with any results, could not make 
> a match )
> 
> And if I need to alter the SRC tag?  Could I do this:
> <xsl:template match="img">
>     <!-- then simply re-create img element, iterate through 
> properties,
> where property is "src" concat and add necessary full path -->
> </xsl:template>

In that case, use xsl:apply-templates to process the contents of $c, add an identity transformation template

  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>

and a template to match the src attribute

  <xsl:template match="@src">
    <xsl:attribute name="src">http://foo.bar.com<xsl:value-of select="."/><xsl:attribute>
  </xsl:template>

> ( If I do that, I don't quite understand where I would 
> apply-templates... )

You read the XPath and XSLT specs or a good book on the subject, makes learning the language a lot easier.

Cheers,

Jarno - Chris C: The Zurich Mix

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