Subject: [xsl] Retrieving the position of an ancestor in nested <xsl:for-each> From: "Jonny Pony" <jonnypony666@xxxxxxxxxxx> Date: Tue, 04 May 2004 10:54:38 +0000 |
<?xml version="1.0" encoding="UTF-8"?> <superNode> <Node> <SubNode>bla</SubNode> <SubNode>bla</SubNode> <SubNode>bla</SubNode> </Node> <Node> <SubNode>bla</SubNode> </Node> <Node> <SubNode>bla</SubNode> <SubNode>bla</SubNode> </Node> <Node> <SubNode>bla</SubNode> </Node> </superNode>
Thanks Jonny
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