Subject: RE: [xsl] Retrieving the position of an ancestor in nested <xsl:for-each> From: <Jarno.Elovirta@xxxxxxxxx> Date: Tue, 4 May 2004 14:10:29 +0300 |
Hi, Use a variable to store the node position. > <xsl:for-each select="Node"> > ... <xsl:variable name="node-position" select="position()"/> > <xsl:for-each select="SubNode"> Position of Node: <xsl:value-of select="$node-position"/> Cheers, Jarno - Suicide Commando: Face Of Death (InterSekt Edit By Tactical Sekt)
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