RE: [xsl] Using <xsl:number>

[David Buddrige <dbuddrige@xxxxxxxxx>]

thanks heaps for that - that's solved the problem. 8-)

David.
--- Jarno.Elovirta@xxxxxxxxx wrote:
> Hi,
> 
> > What I want to do is add a sort-order property to
> each
> > Scope tag, which identifies its relative position
> at
> > each level of the heirarchy among its peers only. 
> > That is to say, the sort-order tag should be added
> > like this:
> > 
> > <Data>
> > 	<Scope id="1" sort-order="1">
> > 		<Scope id="2" sort-order="1"/>
> > 		<Scope id="3" sort-order="2"/>
> > 	</Scope>
> > 	<Scope id="4" sort-order="2">
> > 		<Scope id="5" sort-order="1">
> > 			<Scope id="6" sort-order="1"/>
> > 			<Scope id="7" sort-order="2"/>
> > 		</Scope>
> > 		<Scope id="8" sort-order="2">
> > 			<Scope id="9" sort-order="1">
> > 				<Scope id="10" sort-order="1"/>
> > 				<Scope id="11" sort-order="2"/>
> > 			</Scope>
> > 			<Scope id="12" sort-order="2"/>
> > 		</Scope>
> > 	</Scope>
> > 	<Scope id="13" sort-order="3"/>
> > </Data>
> 
>   <xsl:template match="Scope">
>     <xsl:copy>
>       <xsl:attribute name="sort-order">
>         <xsl:number />
>       </xsl:attribute>
>       <xsl:apply-templates select="@* | node()"/>
>     </xsl:copy>
>   </xsl:template>
>   <xsl:template match="@* | node()">
>     <xsl:copy>
>       <xsl:apply-templates select="@* | node()"/>
>     </xsl:copy>
>   </xsl:template>
> 
> If you want to specify the attributes in xsl:number,
> they're
> 
>   <xsl:number level="single" count="Scope"
> from="Scope"/>
> 
> Cheers,
> 
> Jarno - Velvet Acid Christ: The Dead (Alive mix by
> Funker Vogt))
> 
>
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