RE: [xsl] transformation help

Subject: RE: [xsl] transformation help
From: "Michael Kay" <mhk@xxxxxxxxx>
Date: Mon, 14 Jun 2004 08:54:13 +0100
In XSLT 2.0 you can do this with

<xsl:for-each-group select="*" group-starting-with="category">
<category name="{.}">
  <xsl:copy-of select="current-group() except ."/>
</category>
</xsl:for-each-group>

In 1.0, you can do:

<xsl:for-each select="category">
<category name="{.}">
  <xsl:copy-of
select="following-sibling::item[generate-id(preceding-sibling::category[1])
= generate-id(current())]"/>
</category>
</xsl:for-each>

In English, you are copying the following items whose imediately preceding
category is the current category.

Michael Kay 

> -----Original Message-----
> From: Marcus B. Irven [mailto:marcus@xxxxxxxxxxxxxxx] 
> Sent: 14 June 2004 09:20
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] transformation help
> 
> I have an xml doc in the form of
> 
> <doc>
> <category>cat 1</category>
> <item>item 1</item>
> <item>item 2</item>
> <category>cat 1</category>
> <item>item 3</item>
> <item>item 4</item>
> <item>item 5</item>
> </doc>
> 
> and i want to transform it into
> 
> <doc>
> <category name=3D"cat 1">
> <item>item 1</item>
> <item>item 2</item>
> </category>
> <category name=3D"cat 2">
> <item>item 3</item>
> <item>item 4</item>
> <item>item 5</item>
> </category>
> </doc>
> 
> how should i go about this?
> 
> Thanks,
> Marcus
> 
> 
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